I have the following query:
SELECT DISTINCT A.REZ FROM
(
SELECT REGEXP_SUBSTR(P_EQUATION, '([A-Z|a-z|0-9]+)\{([0-9|\+|\-| |\*|\/\)\(]+)\}#([A-Z|a-z|0-9|_]+)#',1, LEVEL) AS REZ FROM DUAL
CONNECT BY REGEXP_SUBSTR(P_EQUATION, '([A-Z|a-z|0-9]+)\{([0-9|\+|\-| |\*|\/\)\(]+)\}#([A-Z|a-z|0-9|_]+)#',1, LEVEL) IS NOT NULL
) A;
If I supplied the following input:
P_EQUATION := 'A123{(01+02)*2}#ACCOUNT_BALANCE# + B123{(20+10)/20}#ACCOUNT_BALANCE#';
It gives me the following:
REZ
-------------------------------------
A123{(01+02)*2}#ACCOUNT_BALANCE#
B123{(20+10)/20}#ACCOUNT_BALANCE#
But, although the minus sign is included in the pattern, if I have added it inside the curly brackets, it will not recognize the text anymore as a match!
ex:
P_EQUATION := 'A123{(01-02)*2}#ACCOUNT_BALANCE#';
I'm not able to find a solution to this, it is freaking me out, especially, when I tried to match the minus sign alone it works, if I tried to match digits alone it also works :(
Oracle appears to be using POSIX style regexes: https://docs.oracle.com/cd/B12037_01/server.101/b10759/ap_posix001.htm#i690819
The backslash is NOT a metacharacter in a POSIX bracket expression. So in POSIX, the regular expression
[\\d]
matches a\\
or ad
The backslashes are probably messing it up, and they're not necessary. You also don't realize that |
is a literal inside a char class (which the comments also pointed out). I have fixed these problems, and I moved the -
to the start of the char class, which allows it to be interpreted as a literal.
Here you go:
([A-Za-z0-9]+)\{([-0-9+ */)(]+)\}#([A-Za-z0-9_]+)#
Couldn't quite figure out the issue with your code but here is one way to do it:
with temp as
(
select 'A123{(01+02)*2}#ACCOUNT_BALANCE# + B123{(20+10)/20}#ACCOUNT_BALANCE#' P_EQUATION from dual union all
select 'A123{(01-02)*2}#ACCOUNT_BALANCE#' P_EQUATION from dual
)
SELECT DISTINCT A.REZ FROM
(
SELECT REGEXP_SUBSTR(P_EQUATION, '[[:alpha:]]+[[:digit:]]+{\([[:digit:]]+\S[[:digit:]]+\)\S[[:digit:]]+}#[[:alpha:]]+_[[:alpha:]]+#',1, LEVEL) AS REZ FROM temp
CONNECT BY REGEXP_SUBSTR(P_EQUATION, '[[:alpha:]]+[[:digit:]]+{\([[:digit:]]+\S[[:digit:]]+\)\S[[:digit:]]+}#[[:alpha:]]+_[[:alpha:]]+#',1, LEVEL) IS NOT NULL
) A;
OUTPUT:
REZ
---------------------------------------
B123{(20+10)/20}#ACCOUNT_BALANCE#
A123{(01-02)*2}#ACCOUNT_BALANCE#
A123{(01+02)*2}#ACCOUNT_BALANCE#
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