C - Printing first letter of a string using pointers

Question

Im currently working on a project for college and i have the following function, which receives a line (string) and divides it into words:

static const char separators[] = {' ','\t',',',';','.','?','!','"','\n',':','\0'}; 

void split(char *line){
    char *token = strtok(line, separators);
    while(token!=NULL) {
        strtolower(token);
        printf("%s \n", token);
        /* rest of code belongs here */
        token = strtok(NULL, separators);
    }
}

For testing purposes, I wanted to print the first letter of the string token , however it prints the whole string and whenever i use other methods (*token, token[0]) it creates an error stating that %s expects type *char and not int .

How can i print only the first letter of the string, for future implementation in my code?

Answer 1

Very simply:

printf("%c\n", *token);

or

printf("%c\n", token[0]);