简体   繁体   中英

How to get Query parameter with JS/jQuery

Can I put in some variable some Parameter from Query String Parameters?

ie

Headers:

General....

Response Headers....

Request Headers....

Query String Parameters: name:john home:london

/page.php?name=john&home=london

I need var nameQuery = john or var homeQuery = london

There is a much better way to get query params than parsing a string.

Now, an official API called URLSearchParams is available, very easy to use.

 var queryString = "?id=1234&action=edit" var queryParams = new URLSearchParams(queryString); // ps you can get the query string by plain JS like // var queryString = window.location.search; console.log(queryParams.has('id')); // true console.log(queryParams.get('action')); // "edit" console.log(queryParams.getAll('action')); // ["edit"] console.log(queryParams.toString()); // "?id=1234&action=edit" queryParams.append('ref', 'top_page') console.log(queryParams.toString()); // "?id=1234&action=edit&ref=top_page" 

You can use split() for this liek bellow,

  var url = window.location.href; var params = url.split('?')[1].split('&'); for(var i =0;i<params.length;i++){ var temp = params[i].split('='); var key = temp[0]; var value = temp[1]; console.log(key +':'+value); } 

Result

   name:john
   home:london

 var url = '/page.php?name=john&home=london'; var params = url.split('?')[1].split('&');//get the url params array seperated from url var queryObj = {}; for(i = 0; i < params.length; i++){ pair = params[i].split('='); //spilt to key and value queryObj[ pair[0] + 'Query' ] = pair[1]; } console.log(queryObj) 

You can use location.search , which will give you:

"?name=john&home=london"

So, using the above info, you can separate them this way:

search = location.search.substr(1).split("&");

Which you will get:

["name=john", "home=london"]

That you can loop and get the values.

var stuff = {};
for (i = 0; i < search.length; i++) {
  thing = search[i].split("=");
  stuff[thing[0]] = thing[1];
}

And finally, logging stuff you get:

Object {name: "john", home: "london"}

You can use:

stuff.name; // john
stuff.home; // london

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM