SQL query with distinct values while using inner join

Question

avoid Previous posted question.

I am using inner join to join the table, lotid and date is from test table and worker is from test1 table. I am using group by but it is not working because worker and date column is different

lotid worker date
1234  abc    02/02/2106
1234  xyz    03/03/2016

but in the output I should get only 1 lotid

lotid worker date
1234   abc   02/02/2016

how to achieve that?

Answer 1

I make simple table and simple query use DENSE_RANK() below

CREATE TABLE #test (lotid NVARCHAR(10), workDate DATETIME)
CREATE TABLE #test1 (lotid NVARCHAR(10),worker NVARCHAR(10) )

INSERT INTO #test VALUES ('1234','2016-02-02'),('1234','2016-03-03')

INSERT INTO #test1 VALUES ('1234','abc'),('1234','xyz')


SELECT *
FROM (
    SELECT DISTINCT t.*
        ,DENSE_RANK() OVER (PARTITION BY t.lotid ORDER BY t.workDate ASC) AS [r]
    FROM #test t 
    INNER JOIN #test1 t1 ON t.lotid = t1.lotid
) q
WHERE q.r = 1

DROP TABLE #test
DROP TABLE #test1

and result is :

lotid | workDate | r

1234 | 2016-02-02 00:00:00.000 | 1

Answer 2

Thanks for all your helps folks but I figured out the solution,

select lotid,
max(worker) as worker
max(trsdate) as max_date
from test
inner join test1
on test.lotid=test1.lotid
group by lotid