how to link php, sql, and Javascript together,
Question
I'm doing a log in page, i have javascript doing validations ( checking if field is blank) sql storing the data and php doing what php does (idk).... anyway when I press submit it tells me Cannot POST /login.php
is there away to test it on a website and see if it actually works or is the code completely wrong.
<?php
$server = 'localhost';
$username = 'root';
$passowrd = 'cosc_453';
$dbname = 'login'
if(!empty($_POST['user']))
{ $query = mysql_query("SELECT * FROM UserName where userName ='$_POST[user]' AND pass = '$_POST[pass]'") or die(mysql_error());
$row = mysql_fetch_array($query) or die(mysql_error());
{ $_SESSION['userName'] = $row['pass']; echo "SUCCESSFULLY LOGIN TO USER PROFILE PAGE..."; }
else { echo "SORRY... YOU ENTERD WRONG ID AND PASSWORD... PLEASE RETRY...";
}
}
}
if(isset($_POST['submit']))
{ SignIn();
} ?>
php external
function validate(){
if ( document.getElementById (user).value=="")
{
alert ("Please enter your user name");
}
else if ( document.getElementById(pass).value=="")
alert("Please enter you password");
else {
alert("Processing Login........");
}
}
javscript external
CREATE TABLE UserName (
UserNameID int(9) NOT NULL auto_increment,
userName VARCHAR(40) NOT NULL,
pass VARCHAR(40) NOT NULL,
PRIMARY KEY(UserNameID) );
INSERT INTO
UserName (userName, pass)
VALUES
("cosc" , "453");
sql external
<!DOCTYPE HTML>
<html>
<head>
<title>Sign-In</title>
<link rel="stylesheet" type="text/css" href="home.css">
<script src ="login.js"></script>
</head>
<body id="body-color">
<div id="Sign-In">
<fieldset style="width:30%">
<legend>LOG-IN HERE</legend>
<form method="Post" action="login.php" submit =" validate()">
User:<br><input type="text" name="user" size="40"><br>
Password:<br><input type="password" name="pass" size="40"><br>
<input id="button" type="submit" name="submit" value="Log-In">
</form>
< /fieldset>
</div>
</body>
</html>
2 answers
solution1
0 2016-05-12 04:17:10
Your mysql do not have a connection to database. And please stop using mysql, use mysqli instead
<?php
$con = mysqli_connect("localhost","root","cosc_453","login");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM UserName WHERE userName ='".$_POST[user]."' AND pass = '".$_POST[pass]."'";
$result = mysqli_query($conn,$sql);
$count_result = mysqli_num_rows($result);
// Login Success URL
if($count_result == 1)
{
// If you validate the user you may set the user cookies/sessions here
#setcookie("logged_in", "user_id");
#$_SESSION["logged_user"] = "user_id";
$_SESSION["secret_id"] = $row['secret_id'];
if($row['level'] == 1)
{
// Set the redirect url after successful login for admin
$resp['redirect_url'] = 'admin/';
}
else if($row['level'] == 2)
{
// Set the redirect url after successful login for user
$resp['redirect_url'] = 'user/';
}
}
else
{
echo "Invalid username or pass";
}
?>
solution2
0 2016-05-12 05:08:15
To add onto what Eh Ezani stated, you have an issue in your HTML. Your form attribute reads submit when I believe what you meant is onsubmit. Might want to try something like.
<form method="Post" action="login.php" onsubmit ="return validate()">
User:<br><input type="text" name="user" size="40"><br>
Password:<br><input type="password" name="pass" size="40"><br>
<input id="button" type="submit" name="submit" value="Log-In">
</form>
Also, "Use MySQLi over the older MySQL functions. The "i" stands for "improved". The list of improvements can be found in the docs .
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