I have 2 structs interlinked. These forming a linked list.
typedef struct {
char *text;
int count;
} *Item;
typedef struct node {
Item item;
struct node *next;
} *link;
I am building a lookup function to compare the Item structs.
link lookup(link head, Item item){
link list;
for(list = head; list != NULL; list = list->next)
if(strcmp(list->item->text, item->text) == 0)
return list;
return NULL;
}
More specifically, can I do list->item->text on the if statement or do I have to do (*list).(*item).text ? Or is this not possible at all?
You can do what you want, except you used the wrong syntax for the second form. The following are equivalent:
list->item->text
and:
(*(*list).item).text
What you had, (*list).(*item).text
, will cause a syntax error, since you must have a structure member after the .
operator.
Can I do
list->item->text
on the if statement?
Yes, since both are pointers.
Recall that a->b
is the same as (*a).b
.
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