How to figure out how many exceptions raised python

Question

I want to find out the number of raised exceptions and use it with if statement. To be more clear: If it raises more than 10 TimeoutException following one after another, print "There is a problem with website". I searched for it but I couldn't find anything. I hope there is a efficent way to do this.

Here is the code:

while True:
    try:
        browser.get("url")
        return
    except selenium.common.exceptions.TimeoutException:
        print "Timeout"

What I want to do is: If it raises more than 10 Timeout exceptions, print "There is a problem with website"

Answer 1

Just keep track of the number of times the exception has been raised in a counter. Try something like:

count = 1

while True:
    try:
        browser.get("url")
    except selenium.common.exceptions.TimeoutException:
        count += 1
        if count >= 10:
            print 'There is a problem with website'
            break