I have a column with data in the following format:
xxxx(yyyy)
I want to remove what is inside the parentheses, and the parentheses themselves.
I would use a regular expression for this job:
Sub DeleteMatches()
Dim cell As Range, re As Object
' define the regular expression to match "(...)" '
Set re = CreateObject("VBScript.RegExp")
re.Pattern = "\([^)]*\)" ' matches "(...)" '
' iterate and clean each cell in range "C2:C100" '
For Each cell In Range("C2:C100")
cell.Value = re.Replace(cell.Value, Empty)
Next
End Sub
You can readily cater for multiple replacements in one string with a Regexp
Sub Test()
Debug.Print CleanStr("xxxx(yyyy)")
Debug.Print CleanStr("and me ()")
Debug.Print CleanStr("and me ()` second string(aaa)")
End Sub
clean string
Function CleanStr(strIn As String) As String
Dim objRegex As Object
Set objRegex = CreateObject("vbscript.regexp")
With objRegex
.Pattern = "\([^)]*\)"
.Global = True
CleanStr = .Replace(strIn, vbNullString)
End With
End Function
尝试这个:
=LEFT(A1,FIND("(",A1)-1)
Select the cells you wish to process and run this short macro:
Sub DataGrabber()
Dim r As Range
For Each r In Intersect(ActiveSheet.UsedRange, Selection)
If InStr(1, r.Value, "(") > 0 Then
r.Value = Split(r.Value, "(")(0)
End If
Next r
End Sub
Dim x
x = Split("xxxx(yyyy)", "(")
Dim result
result = x(0)
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