PHP how can i hide part of url

Question

I'm working on a project and need to hide part of a url on the output result of my php file, how can i do that?

the piece of code

    if (!$foundPlaylist){
                $playList=array(                
['publishedAt'], 
                            'thumbId'     => $entry[$i]['snippet']['thumbnails']['medium']['url'],
                            'videosCount' => $videoCount,
                            'videos'      => getVideos($entry[$i]['snippet']['resourceId']['videoId']) 
                        );
                array_push($MainFeed,$playList);    
            }

The result

{ "feed":[{"thumbId":"https://i.ytimg.com/vi/SEchOz24pd8/mqdefault.jpg","videosCount":20,"videoid":"SEchOz24pd8",}],"0":

I need to hide https://i.ytimg.com/vi/ and /mqdefault.jpg from thumbId.

Answer 1

Just use

substr($entry[$i]['snippet']['thumbnails']['medium']['url'], 23, 11);

to select only the part of the URL between position 23 and (23+11) = 34

This, of course, only works if you know the string length is going to be exactly the same for all users. If you know the string length will differ, Anthony's answer might help you out.

Answer 2

I find this most readable:

$path = parse_url(
    $entry[$i]['snippet']['thumbnails']['medium']['url'],
    PHP_URL_PATH
);
list($user, $code, $image) = explode('/', $path);

echo $code;