Getting the name of a variable function expression?

Question

The problem

I need to fetch the name of an anonymous function defined as an expression when it is called.

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What I've tried so far

In the following example, I am able to console.log the name of the function like this:

function init() {
    console.log(init.name); // Outputs "init".
}

The console.log will output init respectively. When I define the function as an expression, console.log(init.name); will no longer output init , because technically I'm asking for the name of an anonymous function (as proven by console.log(init); in the second example).

var init = function() {
    console.log(init.name); // Outputs nothing.
};

The following example will initially solve the problem, as suggested by robertklep:

var init = function init() {
    console.log(init.name); // Outputs "init".
};

This way, I give the anonymous function a name and I can just fetch the name with init.name . Although, this is not the solution I'm looking for.

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The question

Is it possible to obtain the name of an anonymous function defined as an expression when it is called at all? Am I forced to give the function a name too if I want to achieve this?

Answer 1

You can't, because coded like that, it's an anonymous function (in other words: it doesn't have a name).

But you can give it a name if you like:

var init = function theFunctionName() {
  console.log(init.name); // outputs: theFunctionName
};

Answer 2

Anonymous function without having any name will give black string if you try .name .

var init = function() {
  console.log(typeof init.name);// will give blank string 
};

But if you give name to function it will give you name.

Answer 3

您可以这样尝试：

console.log(init.toString());