how to use preg_replace() in php?

Question

Can anybody help me with preg_replace? I have an string where I need to filter this out:

health=0.30799794

"health=" Is there in the string every time. But the number behind is different. Is there a way to do it with perg_replace in PHP?

Answer 1

May be you are looking for this:

$filter = '/health=0.30799794/';
$str = 'I am not here and my health=0.30799794';

echo $str = preg_replace ($filter, "", $str); //I am not here and my

Updates:

Just change the filter:

$filter = '/health=[0-9]*.[0-9]*/'; OR $filter = '/health=\\d*.\\d*/';

Answer 2

        <?php
            $pattern    = "#(health=[0-9\.]*)#";
            $sample     = "The Student has not got the best health-status - health=0.30799794 and he is not so happy with it.";
            $result     = preg_replace($pattern, "", $sample);

            var_dump($result);
            //DUMPS: The Student has not got the best health-status -  and he is not so happy with it.