这是我的路径示例E:\\test\\img\\sig.jpg
我想让E:\\test\\img
创建目录,我尝试拆分,但它是img,所以我尝试使用Directory.CreateDirectory函数,路径为E:\\test\\img\\sig.jpg\\
说个主意?
The recommended way is to use Path.GetDirectoryName()
:
string file = @"E:\test\img\sig.jpg";
string path = Path.GetDirectoryName(file); // results in @"E:\test\img"
使用Path.GetDirectoryName
返回指定路径字符串的目录信息。
string directoryName = Path.GetDirectoryName(filePath);
The Path
class contains a lot of useful methods for path handling, which are more reliable than manual string manipulation:
var directoryComponent = Path.GetDirectoryName(@"E:\test\img\sig.jpg");
// yields `E:\test\img`
For completeness, I'd like to mention Path.Combine
, which does the opposite:
var dirAndFile = Path.Combine(@"E:\test\img", "sig.jpg");
// no more checking for trailing slashes, hooray!
To create the directory, you can use Directory.Create
. Note that it is not necessary to check if the directory exists first .
Another solution can be :
FileInfo f = new FileInfo(@"E:\test\img\sig.jpg");
if (f.Exists)
{
string dirName= f.DirectoryName;
}
You can try this code to find the directory name. System.IO.FileInfo fi = new System.IO.FileInfo(@"E:\\test\\img\\sig.jpg"); string dirname = fi.DirectoryName;
and to create the directory Directory.CreateDirectory(dirname );
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