JavaScript how to test if one IPv6 address is larger than another?

Question

Given two IPv6 addresses in string format ie "2001:0db8:0000:0000:0000:ff00:0042:8328" and "2001:0db8:0000:0000:0000:ff00:0042:8329"

how can I test if one is larger than the other? IPv4 was easy, convert into an integer value and compare, but IPv6 numbers are so large this becomes unfeasable.

Answer 1

Replace the address by ":" transform individually each term as hexadecimal value.

Compare the final result of each string.

function toHex(str) {
    var hex = '';
    for(var i=0;i<str.length;i++) {
        hex += ''+str.charCodeAt(i).toString(16);
    }
    return hex;
}

Answer 2

Remove : and do a hexa compare for the entire string.

var first = "2001:0db8:0000:0000:0000:ff00:0042:8328".replace(/:/g, "");
var second = "2001:0db8:0000:0000:0000:ff00:0042:8329".replace(/:/g, "");

// compare

Answer 3

如果你不介意使用第三方库，那就是ip-address 。