How to get 2nd highest salary of each employee in employee table which contains more than one entry in employee table

Question

i am not asking about 2nd highest salary in employee table , i am asking about 2nd highest salary of each employee.

click here to see employee table

Answer 1

I think a very quick solution could be like this:

 SELECT MAX(column) FROM table WHERE column < (SELECT MAX(column) FROM table)

Hope it helps-

Answer 2

inner query will return employees with their highest salary and then from out query those highest salaries will be filtered out so you will get the second highest salary

 SELECT MAX(T.salery),T.NAME FROM TABLE T
     INNER JOIN (SELECT MAX(salery),NAME FROM TABLE GROUP BY NAME) TT 
      ON TT.NAME=T.NAME AND TT.SALERY!= T.SALERY 
       GROUP BY T.NAME;

example

mysql> SELECT * FROM payments;
+----+------------+---------+-------+
| id | date       | user_id | value |
+----+------------+---------+-------+
|  1 | 2016-06-22 |       1 |    10 |
|  2 | 2016-06-22 |       3 |    15 |
|  3 | 2016-06-22 |       4 |    20 |
|  4 | 2016-06-23 |       2 |   100 |
|  5 | 2016-06-23 |       1 |   150 |
|  6 | 2016-06-23 |       2 |   340 |
+----+------------+---------+-------+
6 rows in set (0.00 sec)

mysql> select max(value),user_id from payments group by user_id;
+------------+---------+
| max(value) | user_id |
+------------+---------+
|        150 |       1 |
|        340 |       2 |
|         15 |       3 |
|         20 |       4 |
+------------+---------+
4 rows in set (0.00 sec)

mysql> select max(T.value),TT.user_id from payments T inner join (select max(value) as val,user_id from payments group by user_id) TT on T.value!=TT.val and T.user_id=TT.user_id group by T.user_id;;
+--------------+---------+
| max(T.value) | user_id |
+--------------+---------+
|           10 |       1 |
|          100 |       2 |
+--------------+---------+
2 rows in set (0.00 sec)