How to get all employee record bases of second highest salary

Question

I know how to get the second highest salary form database table using by

SELECT MAX(Salary) From Employee WHERE Salary < ( SELECT Max(Salary) FROM Employee);

But I want get all employee records whose salary is second largest salary into tables.

Answer 1

Select * from employee where salary=(
SELECT MAX(Salary) From Employee WHERE Salary < ( SELECT Max(Salary) FROM Employee));

Answer 2

try this. it should work.

select * from Employee where Salary in (SELECT MAX(Salary) From Employee WHERE Salary < ( SELECT Max(Salary) FROM Employee));

Answer 3

Just get all the employees whose salary equals the second highest salary you got:

set @second_top_salary=(
SELECT MAX(salary) FROM Employee 
WHERE salary<( SELECT Max(salary) FROM employee)
);
SELECT * FROM employee WHERE salary=@second_top_salary;

DEMO

Answer 4

使用LIMIT：

SELECT Salary FROM (SELECT Salary FROM Employee ORDER BY Salary DESC LIMIT 2) AS Emp ORDER BY Salary LIMIT 1