I am quite new to programing in swift and I am working on a music app for iOS that adjusts the font size of the text in a UILabel in proportion to the string's length. In my code, I am trying to count the number of characters in the string statement and have it plugged into a formula, but for some reason Xcode gives me the error: Cannot call value of non function type double I tried setting the value to a CGFloat but it still gives me the same error on the "let b = 41.2 - .8(a) line. Thank you so much and sorry if this seems like a basic question.
let title = "Let It Bleed"
AlbumName.text = title
let a = title.characters.count
if ( a <= 19){
let b = 41.2 - .8(a)
let fontsize = CGFloat(b)
AlbumName.font = AlbumName.font.fontWithSize(fontsize)
}
I assume you expect "0.8 times a" with .8(a)
.
Three things:
You need leading 0 to represent fractional values in Swift.
You need explicit operator *
for multiplication.
You need to convert numeric types to match for mathematical operations.
All these included, your line of interest becomes like this:
let b = 41.2 - 0.8 * CGFloat(a)
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