javascript regular expression ignore condition between the text

Question

I have a text for example as below:

"head1>data1,data2,data3|head2>data1,data2,data3|head3>data3,data4,data5**

now I want to replace ">data1..|" with "|"

I am using this: ".replace(/>\\S+\\||>\\S+$/g,"|");"

But this is not helping as it gives me data as below:

"head1|head3|" instead of "head1|head2|head3|"

I am unable to find the right method.

Answer 1

You can use

>\S+?(?:\||$)

See the regex demo

The point is to make \\S+ lazy, and to shorten the pattern we can use place the >\\S+? before the alternation group.

Pattern details :

• >\\S+? - a literal > followed with 1+ non-whitespace symbols but as few as possible up to
• (?:\\||$) - a literal | or the end of string.

Answer 2

A simple approach :), was trying like this

 var str = "head1>data1,data2,data3|head2>data1,data2,data3|head3>data3,data4,data5"; console.log(str.replace(/>[a-z1-9,]+/g,"|").replace(/\\|+/g, "|")); 

>[a-z1-9,]+ will select >data1,data2,data3

and then replaced multiple | with single |

:)

Answer 3

You can use:

>[a-z0-9,]+\\|

and then replace this with single | every time.