RegEx to match 2 or more digits in a string

Question

Suppose I have strings like:

ABC-L-W7P-1423
ABC-L-W7E-87
CH-L-W7-756

I need to grab the number at the end. That number might be 2, 3 or 4 digits. But currently what I have is:

=REGEXREPLACE(B2,"[^0-9]","")

Which of course also grabs the '7' in 'W7P' which I don't want. EDIT:

I also need to match something like this:

CH-M-311-MM

So always a 2, 3 or 4 (or 5) digit number, but I need single digits excluded.

Answer 1

You can use =REGEXEXTRACT with \\b[0-9]{2,4}\\b :

=REGEXEXTRACT(B2, "\b[0-9]{2,4}\b")

See the regex demo .

Details :

• \\b - a leading word boundary
• [0-9]{2,4} - 2 to 4 digits
• \\b - trailing word boundary

In case your 2-4 digits are always preceded with - , you may use

=REGEXREPLACE(B2,"^.*-([0-9]{2,4})\b.*","$1")

See this regex demo

Details :

• ^ - start of string
• .*- - any 0+ chars up to the last - that is followed with...
• ([0-9]{2,4}) - (Group 1 referred to with $1 in the replacement pattern) - 2 to 4 digits
• \\b - a trailing word boundary
• .* - any chars up to the end of string.

Answer 2

I'm not sure which language you use, but if it supports lookarounds, you can assert that there is a - (dash) on the left side.

(?<=-)\d+

See: https://regex101.com/r/sI9zR9/1