I hope all is well. I am writing with regards to a very specific question in R to which I so far was not able to find a solution online. If the question has already been addressed somewhere else, I am sorry for bothering you but would appreciate if you could provide me with the link.
I have 3 separate data sets:
The first one is a list of companies. The second one is a list of years. The third one is a list of countries.
My objective is now to merge these 3 data sets into a new data frame. The final data frame should create a data row for each combination of these 3 variables . This is the reason why I cannot use the merge() function. As a next step, I want to match data along this newly created data frame.
Thank you ever you much for your support - and again sorry if the question has already been addressed elsewhere!
Try merge
:
A <- data.frame(Companies = LETTERS[1:3])
B <- data.frame(Years = 2000:2002)
C <- data.frame(Countries = c("GER", "UK", "US"))
X <- merge(merge(A, B), C)
X
Companies Years Countries
1 A 2000 GER
2 B 2000 GER
3 C 2000 GER
4 A 2001 GER
5 B 2001 GER
6 C 2001 GER
7 A 2002 GER
8 B 2002 GER
9 C 2002 GER
10 A 2000 UK
...
If you have more than 3 variables/factors you could write your own merge function like this:
mergeN <- function(dfs = NULL) {
if(is.null(dfs) | class(dfs) != "list") stop("'dfs' is not a list!")
if(length(dfs) > 1) {
dfs[[1]] <- merge(dfs[[1]], dfs[[2]])
dfs[[2]] <- NULL
Recall(dfs)
} else {
return(dfs[[1]])
}
}
D <- data.frame(Products = letters[24:26])
E <- data.frame(Divisions = c(100,200,300))
mergeN(list(A, B, C, D, E))
This will give you a dataframe of all 3^5 = 243 combinations.
Update due to comments:
A <- data.frame(Companies = LETTERS[1:3])
B <- data.frame(Years = 2000:2002)
C <- data.frame(Countries = c("GER", "UK", "US"))
X <- merge(merge(A, B), C)
Y <- data.frame(Companies = LETTERS[1:3], Years = rep(2000,3), Countries = c("GER", "UK", "US"), Revenues = c(20433,23255,32164))
merge(X, Y, all=T)
Companies Years Countries Revenues
1 A 2000 GER 20433
2 A 2000 UK NA
3 A 2000 US NA
4 A 2001 GER NA
5 A 2001 UK NA
6 A 2001 US NA
7 A 2002 GER NA
8 A 2002 UK NA
9 A 2002 US NA
10 B 2000 GER NA
11 B 2000 UK 23255
12 B 2000 US NA
13 B 2001 GER NA
14 B 2001 UK NA
15 B 2001 US NA
16 B 2002 GER NA
17 B 2002 UK NA
18 B 2002 US NA
19 C 2000 GER NA
20 C 2000 UK NA
21 C 2000 US 32164
22 C 2001 GER NA
23 C 2001 UK NA
24 C 2001 US NA
25 C 2002 GER NA
26 C 2002 UK NA
27 C 2002 US NA
(If you want NA's to be zero: Z[is.na(Z)] <- 0
)
Borrowing input data frames from @Martin, here's an approach that involves placing all your data frames in a list
, and then using Reduce()
:
d1 <- data.frame(Companies = LETTERS[1:3])
d2 <- data.frame(Years = 2000:2002)
d3 <- data.frame(Countries = c("GER", "UK", "US"))
d4 <- data.frame(Companies = LETTERS[1:3], Years = rep(2000,3), Countries = c("GER", "UK", "US"), Revenues = c(20433,23255,32164))
d <- list(d1, d2, d3, d4)
merged_dat <- Reduce(function(...) merge(..., all=T), d)
head(merged_dat)
#> Companies Years Countries Revenues
#> 1 A 2000 GER 20433
#> 2 A 2000 UK NA
#> 3 A 2000 US NA
#> 4 A 2001 GER NA
#> 5 A 2001 UK NA
#> 6 A 2001 US NA
I prefer this because it generalises to as many data frames as you might have.
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