How to save a file to a specific directory and choose the file's name in python?

Question

As the title says, how can I save a file (in this case a previously selected photo) into a specific directory and also name the saved file (I want to name it with today's date - eg: 01-01-2016.jpg)?

Here's some of my code:

import os.path
import datetime
todays_date = datetime.date.today ()

def add_pic (pic):

    if not os.path.exists ("Pictures"):
        os.makedirs ("Pictures")
    photo_name = todays_date + ".jpg"
    pic.save ("Pictures/"photo_name)

I get this error:

TypeError: unsupported operand type(s) for +: 'datetime.date' and 'str'

for this line:

photo_name = todays_date + ".jpg"

Plus, I'm not sure about the last line either, so pls help!

Answer 1

Use .strftime() to "convert a tuple or struct_time representing a time as returned by gmtime() or localtime() to a string as specified by the format argument.":

photo_name = todays_date.strftime('%m-%d-%Y') + ".jpg"
pic.save(os.path.join("Pictures",photo_name))

Also use os.path.join() for a cross-platform method of joining directory to filename.

As @Blckknght says in a comment: please note that '%m-%d-%Y' is something for which you can change order, eg '%Y-%m-%d' is a common variant.

Answer 2

是的，上面的解决方案应该可行，误解你正在做的就是用字符串添加时间值。

Answer 3

This won't work because datetime.date.today() returns a date object. Try converting to string by calling the .__str__() method, the .ctime() method, or the .strftime() method.
See https://docs.python.org/2/library/datetime.html#date-objects .