Select ONLY row with max(id) in SQL SERVER

Question

I have a table A:

ID     | ProductCatId | ProductCode | Price
1      |       1      |  PROD0001   | 2
2      |       2      |  PROD0005   | 2
3      |       2      |  PROD0005   | 2
4      |       3      |  PROD0008   | 2
5      |       5      |  PROD0009   | 2
6      |       7      |  PROD0012   | 2

I want to select ID,ProductCatId,ProductCode,Price with condition: "if ProductCatId exists same value,so get ProductCatId with max(ID)" , like:

ID     | ProductCatId | ProductCode | Price
1      |       1      |  PROD0001   | 2
3      |       2      |  PROD0005   | 2
4      |       3      |  PROD0008   | 2
5      |       5      |  PROD0009   | 2
6      |       7      |  PROD0012   | 2

Answer 1

Go for window function and row_number()

select ID , ProductCatId , ProductCode , Price
  from (
        select ID , ProductCatId , ProductCode , Price, row_number() over (partition by ProductCatId order by ID desc) as rn
         from myTable
        ) as t
  where t.rn = 1

Answer 2

You can try this,

Select Max(ID),ProductCatId,ProductCode,price
From TableName
Group By ProductCatId,ProductCode,price

Answer 3

select 
top 1 with ties
ID,ProductCatId,ProductCode,Price
from
table
order by
row_number() over (partition by productcatid order by id desc)

Answer 4

may use row_number() :

select t.*
from (select t.*,
             row_number() over (partition by ProductCatId order by ID desc) as seqnum
      from @Table t
     ) t
where seqnum = 1
order by ID;

Answer 5

A little shorter:

SELECT DISTINCT 
    max(ID) OVER (PARTITION BY ProductCatId, 
                               ProductCode, 
                               Price) AS ID,
    ProductCatId, 
    ProductCode, 
    Price,
  FROM myTable