I'm current working on a problem that involves splitting a string by each group of characters.
For example,
"111223334456777" #=> ['111','22','333','44','5','6','777']
The way I am currently doing it now is using a enumerator and comparing each character with the next one, and splitting the array that way.
res = []
str = "111223334456777"
group = str[0]
(1...str.length).each do |i|
if str[i] != str[i-1]
res << group
group = str[i]
else
group << str[i]
end
end
res << group
res #=> ['111','22','333','44','5','6','777']
I want to see if I can use regex to do this, which will make this process a lot easier. I understand I could just put this block of code in a method, but I'm curious if regex can be used here.
So what I want to do is
str.split(/some regex/)
to produce the same result. I thought about positive lookahead, but I can't figure out how to have regex recognize that the character is different.
Does anyone have an idea if this is possible?
str = "111333224456777"
str.scan /0+|1+|2+|3+|4+|5+|6+|7+|8+|9+/
#=> ["111", "333", "22", "44", "5", "6", "777"]
or
str.scan(/((\d)\2*)/).map(&:first)
#=> ["111", "333", "22", "44", "5", "6", "777"]
Readers: can the latter be simplified?
The chunk_while
method is what you're looking for here:
str.chars.chunk_while { |b,a| b == a }.map(&:join)
That will break anything where the current character a
doesn't match the previous character b
. If you want to restrict to just numbers you can do some pre-processing.
There's a lot of very handy methods in Enumerable that are worth exploring, and each new version of Ruby seems to add more of them.
Another option which utilises the group_by
method, which returns a hash with each individual number as a key and an array of grouped numbers as the value.
"111223334456777".split('').group_by { |i| i }.values.map(&:join) => => ["111", "22", "333", "44", "5", "6", "777"]
Although it doesn't implement a regex, someone else may find it useful.
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