On click of search button in my form, i want to set some param to url and submit it.
Below is my javascript
function validateSubmitSearch(form) {
if(form.elements["iAccept"].checked == true) {
form.query.value=form.search_query.value;
form.action = "vendor/search";
form.method = "GET";
form.submit();
}
}
This javascript is returning url as http://localhost:8080/Project/vendor/search?query=xxx&search_query=xxx&search=Search
Instead i need it as http://localhost:8080/Project/vendor/search?query=xxx
How this can be done ?
EDIT:
I cannot remove form elements search_query
and search
Here is HTML code
<form class="searchform" onSubmit="validateSubmitSearch(this)">
<input name="query" type="hidden" />
<input name="search_query" class="textbox" type="text" />
<input type="checkbox" id="iAccept" name="iAccept" value="I ACCEPT">
<input name="search" class="button" value="Search" type="submit" /></td>
</form>
When you submit a form with `method="GET", all the input fields in the form will be included as URL parameters. If you want some of them to be left out, you need to remove those inputs from the form.
function validateSubmitSearch(form){
if(form.elements["iAccept"].checked == true)
{
form.query.value=form.search_query.value;
form.action = "vendor/search";
form.method = "GET";
form.seach_query.parentNode.removeChild(form.search_query);
form.search.parentNode.removeChild(form.search);
form.submit();
}
}
}
Also, you should disable the default form submission by returning false
from the onsubmit
code.
<form class="searchform" onsubmit="validateSubmitSearch(this); return false;">
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