Table - Live Search with jQuery

Question

I have been working on a solution for a Live Search on my table of data.

When I search Jim it works as expected :-)

However, when I search Carey , no results appear. Why is this? :-(

Demo: http://jsfiddle.net/L1d7naem/

 $("#search").on("keyup", function() { var value = $(this).val(); $("table tr").each(function(index) { if (index !== 0) { $row = $(this); var id = $row.find("td:first").text(); if (id.indexOf(value) !== 0) { $row.hide(); } else { $row.show(); } } }); }); 

 table, tr, td, th{ border: 1px solid blue; padding: 2px; } table th{ background-color: #999999; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table> <tr><th>Forename</th><th>Surname</th><th>Extension</th></tr> <tr><td>Jim</td><td>Carey</td><td>1945</td></tr> <tr><td>Michael</td><td>Johnson</td><td>1946</td></tr> </table> <br /> <input type="text" id="search" placeholder=" live search"></input> 

Answer 1

Its because of the following line:

var id = $row.find("td:first").text();  

You are working on the first column of table only and "Carey" is in second column of table

Answer 2

The behaviour you want can be achieved with the following corrections in the each loop (also note the < 0 in the condition...):

var id = $.map($row.find('td'), function(element) {
    return $(element).text()
}).join(' ');

if (id.indexOf(value) < 0) {
    $row.hide();
} else {
    $row.show();
}

Answer 3

Try this. You have to iterate through all columns and once you find any match just escape the loop using the return false; within each() function. Also, indexOf returns -1 if string is not found.

 $("#search").on("keyup", function() { var value = $(this).val(); $("table tr").each(function(index) { if (index !== 0) { $row = $(this); $row.find("td").each(function(){ var id = $(this).text(); if (id.indexOf(value) < 0) { $row.hide(); } else { $row.show(); return false; } }); } }); }); 

 table, tr, td, th{ border: 1px solid blue; padding: 2px; } table th{ background-color: #999999; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table> <tr><th>Forename</th><th>Surname</th><th>Extension</th></tr> <tr><td>Jim</td><td>Carey</td><td>1945</td></tr> <tr><td>Michael</td><td>Johnson</td><td>1946</td></tr> </table> <br /> <input type="text" id="search" placeholder=" live search"></input> 

Answer 4

      $("#search").on("keyup", function() {
    var value = $(this).val();

    $("table tr").each(function(index) {
        if (index !== 0) {

            $row = $(this);

            var id = $.map($row.find('td'), function(element) {
    return $(element).text()
}).join(' ');





            if (id.indexOf(value) <0) {
                $row.hide();
            }
            else {
                $row.show();
            }
        }
    });
});

http://jsfiddle.net/Lyxex4tp/

Answer 5

Try this:

$("#search").on("keyup", function() {
var value = $(this).val();

$("table td").each(function() {
    if(value.match($(this).text)) {
        console.log($(this).text());
    }

    else {
        $("table").hide();
    }
});
});

Try matching with all the td elements.

Answer 6

Hope this works,

$("#search").on("keyup", function() {
var value = $(this).val();

$("table tr").each(function(index) {
    if (index !== 0) {
        var id = $(this).children().text()
        if (id.indexOf(value) < 0) {
           $(this).hide();
        }else {
            $(this).show();
        }
    }
 });
});

Here is the working fiddle https://jsfiddle.net/44Lux7ze/