I have the following list in Python.
[('a1',
[('b', 1),
('c', 2),
('d', 3),
('e', 4),
('f', 5),
('g', 6]),
('a2',
[('c', 7),
('f', 8),
('g', 9),
('b', 1),
('e', 2),
('d', 3)])]
I would like to save the list as the following format in csv:
a1 a2
b 1 c 7
c 2 f 8
d 3 g 9
e 4 b 1
f 5 e 2
g 6 d 3
The csv format is quite simple.
To start to know how to that, just create a csv file with the output you want, and open it with any text editor, you will obtain:
a1,,a2,
b,1,c,7
c,2,f,8
d,3,g,9
e,4,b,1
f,5,e,2
g,6,d,3
So here is the code you need, but should have at least to obtain alone.
input_list = [('a1', [('b', 1), ('c', 2), ('d', 3), ('e', 4), ('f', 5), ('g', 6)]), ('a2', [('c', 7), ('f', 8), ('g', 9), ('b', 1), ('e', 2), ('d', 3)])]
with open("my_file.csv", 'w') as f:
first_line = [x[0] + ',' for x in input_list]
f.write(",".join(first_line) + "\n")
for x,y in zip(input_list[0][1], input_list[1][1]):
k1, v1 = x
k2, v2 = y
f.write("{k1},{v1},{k2},{v2}\n".format(k1=k1, v1=v1, k2=k2, v2=v2))
An other solution is to use the csv module . And there are some examples in the doc.
This should get you started:
>>> a = [('b', 1), ('c', 2)]
>>> b = [('c', 7), ('f', 8)]
>>>
>>> for x,y in zip(a,b):
... k1, v1 = x
... k2, v2 = y
... print("{k1} {v1} {k2} {v2}".format(k1=k1, v1=v1, k2=k2, v2=v2))
...
b 1 c 7
c 2 f 8
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