how to find if a string contains two dot in regular expression in php

Question

I want to know if the string contains two . . for example if the string contains www.example.com , returns true ,because it has 2 . , otherwise has less than 1 . return false.

function containsTwoDot($array,$keyword){
   $matches = array_filter($array, function($var) use ($keyword) { return preg_match("/\b".$keyword."\b/i".$keyword, $var); });
   if($matches)
        return true;
   return FALSE;
}

$true[0]='www.sll.dl';
$false[0]='ldfjls.dlfjdflldl';

Answer 1

You can use php function substr_count() -

<?php
$text = 'www.example.com';
echo substr_count($text, '.'); // 2
?>

of course it doesn't return true or false .That you can manage.

Answer 2

Use preg_match and escape dots cause it's special chars:

$string = 'www.example.com';

preg_match('/\..*\./',$string);