I am trying to solve differential heat equation using Thomas algorithm.
Physical problem : We have plug, left side is having temperature 0
, right side temperature is 1
.
For Thomas algorithm I have written a function, which accept three QVector
and int
value amount of equations.
This is my code:
#include <QCoreApplication>
#include <QVector>
#include <QDebug>
#include <iostream>
using std::cin;
void enterIn(QVector<float> &Array, int Amount_of_elements){
int transit;
for(int i=0;i<Amount_of_elements;i++){
cin>>transit;
Array.push_back(transit);
}
}
QVector<float> shuttle_method(const QVector<float> &below_main_diagonal,
QVector<float> &main_diagonal,
const QVector<float> &beyond_main_diagonal,
const QVector<float> &free_term,
const int N){
QVector <float> c;
QVector <float> d;
for(int i=0;i<N;i++){
main_diagonal[i]*=(-1);
}
QVector<float> x; //result
c.push_back(beyond_main_diagonal[0]/main_diagonal[0]);
d.push_back(-free_term[0]/main_diagonal[0]);
for(int i=1;i<=N-2;i++){
c.push_back(beyond_main_diagonal[i]/(main_diagonal[i]-below_main_diagonal[i]*c[i-1]));
d.push_back( (below_main_diagonal[i]*d[i-1] - free_term[i]) / (main_diagonal[i]- below_main_diagonal[i]*c[i-1]) );
}
x.resize(N);
//qDebug()<<x.size()<<endl;
int n=N-1;
x[n]=(below_main_diagonal[n]*d[n-1]-free_term[n])/(main_diagonal[n]-below_main_diagonal[n]*c[n-1]);
for(int i=n-1;i>=0;i--){
x[i]=c[i]*x[i+1]+d[i];
// qDebug()<<x[i]<<endl;
}
return x;
}
int main()
{
QVector <float> alpha; // below
QVector <float> beta; // main diagonal * (-1)
QVector <float> gamma; // beyond
QVector <float> b; // free term
QVector<float> T;
int cells_x=40; //amount of equations
alpha.resize(cells_x);
beta.resize(cells_x);
gamma.resize(cells_x);
b.resize(cells_x);
T.resize(cells_x);
float dt=0.2,h=0.1;
alpha[0]=0;
for(int i=1;i<cells_x;i++){
alpha[i]= -dt/(h*h);
}
for(int i=0;i<cells_x;i++){
beta[i] = (2*dt)/(h*h)+1;
}
for(int i=0;i<cells_x-1;i++){
gamma[i]= -dt/(h*h);
}
gamma[cells_x-1]=0;
qDebug()<<"alpha= "<<endl<<alpha.size()<<alpha<<endl<<"beta = "<<endl<<beta.size()<<beta<<endl<<"gamma= "<<gamma.size()<<gamma<<endl;
for(int i=0;i<cells_x-1;i++){
T[i]=0;
}
T[cells_x-1]=1;
qDebug()<<endl<<endl<<T<<endl;
//qDebug()<< shuttle_method(alpha,beta,gamma,b,N);
QVector<float> Tn;
Tn.resize(cells_x);
Tn = shuttle_method(alpha,beta,gamma,T,cells_x);
Tn[0]=0;Tn[cells_x-1]=1;
for(int stepTime = 0; stepTime < 50; stepTime++){
Tn = shuttle_method(alpha,beta,gamma,Tn,cells_x);
Tn[0]=0;
Tn[cells_x-1]=1;
qDebug()<<Tn<<endl;
}
return 0;
}
My problem is: when I compile and run it I am getting this:
Tn <20 items> QVector<float>
0 float
0.000425464 float
0.000664658 float
0.000937085 float
0.00125637 float
0.00163846 float
0.00210249 float
0.00267163 float
0.00337436 float
0.00424581 float
0.00532955 float
0.00667976 float
0.00836396 float
0.0104664 float
0.0130921 float
0.0163724 float
0.0204714 float
0.0255939 float
0.0319961 float
Tn <20 items> QVector<float>
0 float
-0.000425464 float
0.000643385 float
-0.000926707 float
0.00120951 float
-0.00161561 float
0.00202056 float
-0.00263167 float
0.00324078 float
-0.00418065 float
0.00511726 float
-0.00657621 float
0.00802998 float
-0.0103034 float
0.0125688 float
-0.0161171 float
0.0196527 float
-0.0251945 float
0.0307164 float
1 float
Tn <20 items> QVector<float>
0 float
0.000425464 float
0.000664658 float
0.000937085 float
0.00125637 float
0.00163846 float
0.00210249 float
0.00267163 float
0.00337436 float
0.00424581 float
0.00532955 float
0.00667976 float
0.00836396 float
0.0104664 float
0.0130921 float
0.0163724 float
0.0204714 float
0.0255939 float
0.0319961 float
Tn <20 items> QVector<float>
0 float
-0.000425464 float
0.000643385 float
-0.000926707 float
0.00120951 float
-0.00161561 float
0.00202056 float
-0.00263167 float
0.00324078 float
-0.00418065 float
0.00511726 float
-0.00657621 float
0.00802998 float
-0.0103034 float
0.0125688 float
-0.0161171 float
0.0196527 float
-0.0251945 float
0.0307164 float
1 float
Again and again in loop.
I have no idea why I am getting this.
Maybe my mistake is in assign Tn
result of my Thomas-method-function?
or in realization of Thomas method? or in boundary conditions?
I got it!
Boundary conditions must be acting to vectors
QVector<float> below_main_diagonal,
QVector<float> main_diagonal,
QVector<float> beyond_main_diagonal
so that T[0] must be 0 and T[N-1] must be 1. We can do it this way:
main_diagonal.first()=1;
main_diagonal.last()=1;
beyond_main_diagonal.first()=0;
below_main_diagonal.last()=0;
and due to this T[0] will be always equal to zero and T[N-1] will be equal to 1;
And in the article where I read about Thomas method the first step was to negate main diagonal, I have done it, but then in the end of the function I must do reverse thing, so:
for(int i(0);i<N;++i){
main_diagonal[i]*=(-1);
}
and we can use this function again, this is not absolutely optimal, but it is working stable.
Then, the whole code will be look like this:
#include <QCoreApplication>
#include <QVector>
#include <QDebug>
#include <iostream>
QVector<float> Thomas_Algorithm( QVector<float> &below_main_diagonal ,
QVector<float> &main_diagonal ,
QVector<float> &beyond_main_diagonal ,
QVector<float> &free_term,
const int N){
QVector<float> x; //vector of result
// checking of input data
if(below_main_diagonal.size()!=main_diagonal.size()||
main_diagonal.size()!=beyond_main_diagonal.size()||
free_term.size()!=main_diagonal.size())
{ qDebug()<<"Error!\n"
"Error with accepting Arrays! Dimensities are different!"<<endl;
x.resize(0);
return x;
}
if(below_main_diagonal[0]!=0){
qDebug()<< "Error!\n"
"First element of below_main_diagonal must be equal to zero!"<<endl;
x.resize(0);
return x;
}
if(beyond_main_diagonal.last()!=0){
qDebug()<< "Error!\n"
"Last element of beyond_main_diagonal must be equal to zero!"<<endl;
x.resize(0);
return x;
}
// end of checking
QVector <float> c;
QVector <float> d;
for(int i=0;i<N;i++){
main_diagonal[i]*=(-1);
}
c.push_back(beyond_main_diagonal[0]/main_diagonal[0]);
d.push_back(-free_term[0]/main_diagonal[0]);
for(int i=1;i<=N-2;i++){
c.push_back(beyond_main_diagonal[i]/(main_diagonal[i]-below_main_diagonal[i]*c[i-1]));
d.push_back( (below_main_diagonal[i]*d[i-1] - free_term[i]) /
(main_diagonal[i]- below_main_diagonal[i]*c[i-1]) );
}
x.resize(N);
int n=N-1;
x[n]=(below_main_diagonal[n]*d[n-1]-free_term[n])/(main_diagonal[n]-below_main_diagonal[n]*c[n-1]);
for(int i=n-1;i>=0;i--){
x[i]=c[i]*x[i+1]+d[i];
}
for(int i(0);i<N;++i){
main_diagonal[i]*=(-1);
}
return x;
}
int main()
{
QVector <float> alpha; // below
QVector <float> beta; // main diagonal * (-1)
QVector <float> gamma; // beyond
QVector <float> b; // free term
QVector<float> T;
int cells_x=30; // amount of steps
alpha.resize(cells_x);
beta.resize(cells_x);
gamma.resize(cells_x);
T.resize(cells_x );
float dt=0.2,h=0.1;
alpha[0]=0;
for(int i=1;i<cells_x-1;i++){
alpha[i]= -dt/(h*h);
}
alpha[cells_x-1]=0;
beta[0]=1;
for(int i=1;i<cells_x-1;i++){
beta[i] = (2*dt)/(h*h)+1;
}
beta[cells_x-1]=1;
gamma[0]=0;
for(int i=1;i<cells_x-1;i++){
gamma[i]= -dt/(h*h);
}
gamma[cells_x-1]=0;
for(int i=0;i<cells_x-1;i++){
T[i]=0;
}
T[cells_x-1]=1;
QVector<float>Tn;
Tn.resize(cells_x);
Tn= Thomas_Algorithm(alpha,beta,gamma,T,cells_x);
// boundary conditions!
beta.first()=1;
beta.last()=1;
gamma.first()=0;
alpha.last()=0;
// and then due to bc we always have T[0]=0 and T[n]=1
for(int stepTime=0;stepTime<100;stepTime++){
Tn = Thomas_Algorithm(alpha,beta,gamma,Tn,cells_x);
qDebug()<<"stepTime = "<<stepTime<<endl<<endl;
qDebug()<<Tn<<endl;
// boundary conditions!
beta.first()=1;
beta.last()=1;
gamma.first()=0;
alpha.last()=0;
// and then due to bc we always have T[0]=0 and T[n]=1
}
return 0;
}
and in the last step we are going to get absolutely "physical" results:
Tn <30 items> QVector<float>
0 float
0.0344828 float
0.0689656 float
0.103448 float
0.137931 float
0.172414 float
0.206897 float
0.24138 float
0.275862 float
0.310345 float
0.344828 float
0.379311 float
0.413793 float
0.448276 float
0.482759 float
0.517242 float
0.551724 float
0.586207 float
0.62069 float
0.655173 float
0.689655 float
0.724138 float
0.758621 float
0.793104 float
0.827586 float
0.862069 float
0.896552 float
0.931035 float
0.965517 float
1 float
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