regex to replace any word with two capital letters

Question

I want to replace any word which contains two capital letters .

here is my string

jennie-garth-jennie-garth-inner-city-arts-gala-october-17-2012-If9aSpTW
jennie-garth-jennie-garth3892-H9rDcbY 

i want to replace -If9aSpTW with -

These -If9aSpTW varies so I can't use str_replace . I can identify with only two capital letter in one word. These words are at the end, but these types of words are appearing for 20% of total database values so I can't replace all last words.

Answer 1

The str_replace is context unaware, nor can you use substr since you need to check for 2 uppercase letters in the last non-hyphen chunk of the text. So you really have to stick to preg_replace regex based replacement.

You may use the following regex:

preg_replace('/-(?:[^-]*[A-Z]){2,}[^-]*$/', '', $str);

See the regex demo .

The pattern matches:

• - - a hyphen
• (?:[^-]*[AZ]){2,} - 2 or more occurrences (due to {2,} limiting quantifier) of a sequence of:
  • [^-]*
  • [AZ] - an uppercase
• [^-]* - zero or more chars other than -
• $ - end of string

PHP :

$str = 'jennie-garth-jennie-garth-inner-city-arts-gala-october-17-2012-If9aSpTWe';
echo preg_replace('/-(?:[^-]*[A-Z]){2,}[^-]*$/', '', $str);