Linked-List: read String in C

Question

I need to read string (line by line) from a file and store them to linked list. I can read from file and print them. However, I have issue how to store them to linked list. I tried to create linked-list and save them like below:

#include <stdio.h>
#include <stdlib.h>


typedef struct node
{
    char data[256];
    struct node *next;

} node_t;

node_t *head = NULL;
node_t *current = NULL;

int main(int argc, char const *argv[])
{
    char temp = 'Hello';
    insertToHead(temp);
    return 0;
}

void insertToHead(char *word) 
{
    node_t *link = (node_t *) malloc(sizeof(node_t));

    link->data = strcpy(link->data , word);

    link->next = head;
    head = link;
}

Answer 1

There are many issues.

I fixed the here and now the program compiles at least:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


typedef struct node
{
    char data[256];
    struct node *next;

} node_t;

node_t *head = NULL;
node_t *current = NULL;

void insertToHead(char *word) 
{
    node_t *link = (node_t *) malloc(sizeof(node_t));

    strcpy(link->data , word);

    link->next = head;
    head = link;
}

int main(int argc, char const *argv[])
{
    char *temp = "Hello";
    insertToHead(temp);
    return 0;
}

You really should learn how to read the output of your compiler.

Answer 2

There were quite a few syntactic problems and you should include the string library:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct node {
  char data[256];
  struct node *next;
} node_t;

node_t *head = NULL;
node_t *current = NULL;

void insertToHead(char *word) {
  node_t *link = (node_t *) malloc(sizeof(node_t));

  strcpy(link->data , word);

  link->next = head;
  head = link;
}

int main(int argc, char const *argv[]) {
  char *temp = "Hello";

  insertToHead(temp);
  return 0;
}

EDIT

I was trying to solve the issue when @MichaelWalz already posted the solution