Find shell script and rename row

Question

I have shell script with name script.sh. I need to find this script and change value inside script

From:

bash $current_dir/run.sh

to

./run.sh.x

my solution is something like:

find -maxdepth 10 -name "script.sh" -exec sed -i 's#bash '$current_dir'#run.sh#.#runs.sh.x#' {} \ ;

But still my command does not work. Any idea how to replace this string in new string in my shell script?

Answer 1

Your sed expression seems to be the issue.

You can use:

find . -maxdepth 10 -name "script.sh" -exec sed -i 's#bash \$current_dir/run\.sh#./run.sh.x#' {} +

Answer 2

@anubhava is correct. Another sed command which you can use.

find . -maxdepth 10 -name "script.sh" -type f | xargs -I {} sed -i 's/.*\/run.sh/\.\/run.sh.x/g' {}

Answer 3

One way to sidestep sed compatibility issues is to rely on perl . Adopting an answer from BashFAQ #21 :

search='bash $current_dir/run.sh'
replace='./run.sh.x'
in="$search" out="$replace" find . -name script.sh -exec \
  perl -pi -e 's/\Q$ENV{"in"}/$ENV{"out"}/g' '{}' +