I used this code to concatenate two strings in C:
int main(int argc, char** argv) {
char a[] = "hello ";
char b[] = "world";
concat(a, b);
printf("%s\n", a);
return (EXIT_SUCCESS);
}
void concat(char s[], char t[]){
int i, j;
i = j = 0;
while (s[i] != '\0') i++;
while ((s[i++]=t[j++]) != '\0');
}
The string was concatenated correctly but the next line in output was:
*** stack smashing detected *** [...] terminated
Why was this code detected as stack smashing?
char a[] = "hello ";
This declares a char
array with exactly 7 elements, the six characters plus \\0
. There's no room for anything to be concatenated.
A simple fix is to reserve more space, if you know how much data you want to add.
char a[12] = "hello ";
Strings in C are set length, thus you can't append something to them. You have to create a new one and copy both to it. The error is triggered because you are writing to a space that wasn't allocated to you. You got only 7 bytes, but you are writing 8th, 9th... 12th byte, thus owerwriting other program data (smashing the stack).
#include <string.h>
char* concat(char s[], char t[]){
int i, j;
i = j = 0;
char* u = (char*)malloc(strlen(s) + strlen(t)+1);//new string with enough space for both and \0
while (s[i] != '\0') {
u[i]=s[i];
i++;
}
while ((u[i++]=t[j++]) != '\0');
return u;
}
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