I'm new to C++ and stack overflow in general so please excuse me if a make a mistake somewhere. I posted my code down below, but my issue is that when I type either yes
or no
at after the calculation is complete, no
is supposed to end the program (which I was still working on) and yes
is supposed to set it up for another calculation.
However I end up with a glitchy loop.
#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
bool b;
bool yes = b;
do {
float x;
float y;
float z;
float a;
cout << "Enter The amount you are investing:" << endl;
cin >> x;
cout << "Enter the rate:" << endl;
cin >> y;
cout << "Enter the investment period (years):" << endl;
cin >> z;
cout << "Enter the compounding period:" << endl;
cin >> a;
cout << pow((1 + y / a), (a*z))*x << endl << "Want to do another? (yes/no)";
cin >> b;
cin.ignore();
} while (yes = true); {
cin.clear();
if (b = yes) {
}
else {
}
}
return 0;
}
The behaviour of your code is probably due to:
unintentional reassignment of the termination condition bool
value: yes
to: true
, instead of checking its value, which is done with ==
, not with the assignment =
.
no modification of the value yes
within the while
loop.
A possible update is:
#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
// initialise the sentinel
bool yes = true;
do {
// define variables
float x, y, z, a;
// read input
cout << "Enter The amount you are investing:" << endl;
cin >> x;
cout << "Enter the rate:" << endl;
cin >> y;
cout << "Enter the investment period (years):" << endl;
cin >> z;
cout << "Enter the compounding period:" << endl;
cin >> a;
cout << pow((1 + y / a), a * z) * x << endl;
// redo calculation or exit
cout << "Want to do another? (yes/no)";
cin >> yes;
// check termination condition
} while (yes == true);
return 0;
}
Additionally, watch out for the uninitialised variables: x
, y
, z
, a
and think for a proper default value that will indicate possible wrong result.
Lastly, withing the calculation: 1 + y / a
is ambiguous, it could mean both: (1 + y) / a
and: 1 + (y / a)
, put parentheses to enforce precedence in the wanted order.
You are not modifying the value of variable yes
. It is always set to true
.
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