Run all shell scripts in folder

Question

I have many .sh scripts in a single folder and would like to run them one after another. A single script can be executed as:

bash wget-some_long_number.sh -H

Assume my directory is /dat/dat1/files

How can I run bash wget-some_long_number.sh -H one after another?

I understand something in these lines should work:

for i in *.sh;...do ....; done

Answer 1

Use this:

for f in *.sh; do
  bash "$f" 
done

If you want to stop the whole execution when a script fails:

for f in *.sh; do
  bash "$f" || break  # execute successfully or break
  # Or more explicitly: if this execution fails, then stop the `for`:
  # if ! bash "$f"; then break; fi
done

It you want to run, eg, x1.sh , x2.sh , ..., x10.sh :

for i in `seq 1 10`; do
  bash "x$i.sh" 
done

To preserve exit code of failed script (responding to @VespaQQ):

#!/bin/bash
set -e
for f in *.sh; do
  bash "$f"
done

Answer 2

有一种更简单的方法，您可以使用run-parts命令来执行文件夹中的所有脚本：

run-parts /path/to/folder

Answer 3

I ran into this problem where I couldn't use loops and run-parts works with cron.

Answer:

foo () {
    bash -H $1 
    #echo $1
    #cat $1
}
cd /dat/dat1/files #change directory
export -f foo #export foo
parallel foo ::: *.sh #equivalent to putting a & in between each script

You use GNU parallel, this executes everything in the directory, with the added buff of it happening at a lot faster rate. Not to mention it isn't just with script execution, you could put any command in the function and it'll work.