I have a pop up menu and inside that I have a form and a text box. I want to retrieve that value and submit it to my controller. Once submitted I want my pop up to close and go back to the other page. I tried with AJAX but I might be doing something wrong.
<form onsubmit="return(testing());" method="POST">
<input type="text" name="vip_text_box" id="vip" value="<?php echo $total_amount ?>"> <br>
<input type="submit" name="Redeem" value="Redeem">
</form>
Now My Javascript
function testing() {
$test = document.getElementById("vip").value;
var url = base_url + '/index.php/home/redeeming_form_value';
$.ajax({
type : 'POST',
url : url,
data : {'myvalue':test},
success: function(data){
alert(data);
}
});
};
In my controller
function redeeming_form_value() {
$amount = $this->input->post('myvalue');
return $amount;
In the AJAQ I have a success, and want to alert my data(the value) to make sure it even works but it does nothing. When i click submit my pop up view just goes away.
Try adding dataType: "json", to your Ajax
dataType: "json",
Then in your controller use json_encode to return your data
$arr = array('amount' => $amount);
return json_encode($arr);
Test the response in success
console.log(data.amount);
Try it..
HTML
<form action="" method="POST">
<input type="text" name="vip_text_box" id="vip" value="<?php echo $total_amount ?>"> <br>
<input type="submit" name="Redeem" id="submit" value="Redeem">
</form>
Javascript
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
var test = $("#vip").val();
var base_url= 'http://localhost/shop';
var url = base_url + '/index.php/home/redeeming_form_value';
$.ajax({
type : 'POST',
dataType: 'json',
url : url,
data :'myvalue='+test,
success: function(data){
msg= eval(data);
amount= msg.amount;
alert(amount);
}
});
});
});
</script>
At your Controller
function redeeming_form_value()
{
$amount = $this->input->post('myvalue');
echo json_encode(array('amount'=>$amount));
}
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