I give the following example to illustrate my question:
class Abc
{
public:
int a;
int b;
int c;
};
class Def
{
public:
const Abc& abc_;
Def(const Abc& abc):abc_(abc) { }
Def& operator = (const Def& obj)
{
// this->abc_(obj.abc_);
// this->abc_ = obj.abc_;
}
};
Here I do not know how to define the copy assignment operator. Do you have any ideas? Thanks.
references cannot be assigned to. You need something that can. A pointer would work, but they're very abusable.
How about std::reference_wrapper
?
#include <functional>
class Abc
{
public:
int a;
int b;
int c;
};
class Def
{
public:
std::reference_wrapper<const Abc> abc_;
Def(const Abc& abc):abc_(abc) { }
// rule of zero now supplies copy/moves for us
// use the reference
Abc const& get_abc() const {
return abc_.get();
}
};
A reference cannot be assigned. Due to this, one can only define it via placement new and copy construction:
Def& operator = (const Def& obj)
{
this->~Def(); // destroy
new (this) Def(obj); // copy construct in place
}
But it is really unnecesary. Just use a pointer.
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