I have an application that uses Spring with the following configuration
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<mvc:annotation-driven/>
<mvc:resources mapping="/*" location="/" />
<context:component-scan base-package="controller" />
And this is the whole web.xml file
<web-app>
<servlet>
<servlet-name>springrest</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springrest</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
The application runs very well on localhost:8080/web, but I want to change it to localhost:8080/web/rest and for doing that I tried to change the url pattern from
<servlet-mapping>
<servlet-name>springrest</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
to
<servlet-mapping>
<servlet-name>springrest</servlet-name>
<url-pattern>/rest</url-pattern>
</servlet-mapping>
But unfortunately it doesn't work, what am I doing wrong?
With your change you are filtering the URL intercepted by the DispatcherServlet to be only those starting with /rest
and not all /
as before, so you are just reducing the number of URL handled by Spring, not changing mappings. This is not what you want, I am afraid is not possible to "move down one level" (from /web
to /web/rest
) a java web application with some web.xml configuration, you should rewrite your mappings in Spring configuration (what was /
is now /rest
, what was /foo
is now /rest/foo
).
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