How to get corresponding values of a key in a JSON object in python where keys are in a different array

Question

I have a JSON object which looks like this

{
'stats': {
    'stats_fields': {}
},
'responseHeader': {
    'stats': 0,
    'QTime': 312
},
'response': {
    'start': 0,
    'maxScore': 4.224531,
    'nmFond': 10,
    'docs': [{
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.14139599,
        'id': '635017352776'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13736124,
        'id': '626248286912'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.14090206,
        'id': '667202821955'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13128135,
        'id': '652653090703'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.15008019,
        'id': '673173069540'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13817552,
        'id': '651864037354'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.1015507,
        'id': '366140762'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.049298372,
        'id': '621955821828'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.037345234,
        'id': '627999851992'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.03293659,
        'id': '647972845012'
    }]
}
}

I have another array having the Ids which looks like this

[626248286912, 366140762, 627999851992, 667202821955, 621955821828, 652653090703, 647972845012, 673173069540, 635017352776, 651864037354]

now i want to create an array having the value of key ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha)))) in the same order as the Ids in the second array . Is there a more efffcient way to do it in python than iterating and comparing the Ids in the json object

Answer 1

First your data is not really json because strings are protected by single quotes and json expects double quotes.

That can be workarounded by using ast.literal_eval for now.

So, I create d using ast.literal_eval so data is correctly converted to python native structure.

Then, I create a dictionary with key=id (as integer) and value as the value beared by the key different from id (using a nested generator comprehension that I consume using next to get the sole element)

After that, it's easy to query each value of the dictionary and compose the list in the required order.

Code:

import ast

js = """{
'stats': {
    'stats_fields': {}
},
'responseHeader': {
    'stats': 0,
    'QTime': 312
},
'response': {
    'start': 0,
    'maxScore': 4.224531,
    'nmFond': 10,
    'docs': [{
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.14139599,
        'id': '635017352776'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13736124,
        'id': '626248286912'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.14090206,
        'id': '667202821955'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13128135,
        'id': '652653090703'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.15008019,
        'id': '673173069540'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.13817552,
        'id': '651864037354'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.1015507,
        'id': '366140762'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.049298372,
        'id': '621955821828'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.037345234,
        'id': '627999851992'
    }, {
        'ml(div(map(abs(hpsaScore_alpha),0,100,abs(hpsaScore_alpha),100),100),ml(0.2,div(abs(hpsaScore_alpha),map(hpsaScore_alpha,0,0,1,hpsaScore_alpha))))': 0.03293659,
        'id': '647972845012'
    }]
}
}"""

idlist = [626248286912, 366140762, 627999851992, 667202821955, 621955821828, 652653090703, 647972845012, 673173069540, 635017352776, 651864037354]

d = ast.literal_eval(js)
by_id = {int(sd['id']):next(v for v in sd.values() if v!=sd['id']) for sd in d['response']['docs']}

result = [(a,by_id[a]) for a in idlist]
print(result)

result (if you just want the values and not the tuples do: [by_id[a] for a in idlist] ):

[(626248286912, 0.13736124), (366140762, 0.1015507), (627999851992, 0.037345234), (667202821955, 0.14090206), (621955821828, 0.049298372), (652653090703, 0.13128135), (647972845012, 0.03293659), (673173069540, 0.15008019), (635017352776, 0.14139599), (651864037354, 0.13817552)]