This is the code :
#include <stdio.h>
int funk1()
{
int N=0;
float a;
FILE *f;
f=fopen("wyniki.txt", "r");
while(fscanf(f,"%f", &a)!=EOF)
{
N++;
}
fclose(f);
return N;
}
void funk2(int N, float T[][N])
{
FILE *f;
f=fopen("wyniki.txt", "r");
float a;
int i=0;
while(fscanf(f,"%f", &a)!=EOF)
{
T[i][0]=a;
T[0][i]=a;
printf("funk 2\n");
printf("liczba = %f i = %d \n", a, i);
printf("%f %f\n", T[i][0], T[0][i]);
i++;
}
fclose(f);
}
main()
{
int N = funk1();
float T[N][N];
funk2(N,T[][N]);
int i=0;
int j=0;
for(i=0;i<N;i++){
for(j=0;j<N;j++){
printf("|%f|\t",T[i][j]);
}
printf("\n");
printf("|%f|\t", T[i][j]);
}
getch();
return 0;
}
The problem is only with funk2. I want to pass the matrix (T) from main to funk2, do stuff with it and then give it back to main. I have no idea how to do that to be honest, I just tried out messing with it but it doesn't work. Any idea how to do that? Should I provide more information or is this enough? You can ignore the first function and the first half of funk2 as well. It all works just fine, the problem I have only has to do with passing the twodimensional array.
The result of this code is an error in
funk2(N,T[][N]);
(expected expression before ']' token).
Adding an N there results in
expected 'float (*)[(sizetype)(N)]' but argument is of type 'float'
The only time []
is valid syntax is when declaring an array either with an initializer or as a function parameter.
If you want to pass an array to a function, just pass it:
funk2(N,T);
You don't need to call out the dimensions of the array. The compiler knows it's an array.
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