//V4.cpp
#include <iostream>
using namespace std;
class V3 {
private:
double x, y, z;
public:
V3(double a, double b, double c): x(a), y(b), z(c) {
cout << "V3(double, double, double)" << endl;
}
V3(const V3 &a): x(a.x), y(a.y), z(a.z) {
cout << "V3(const V3 &)" << endl;
}
};
class V4 {
private:
V3 xyz;
double time;
public:
V4(V3 a, double t): xyz(a), time(t) {
cout << "V4(V3, double)" << endl;
}
};
int main(void)
{
V3 xyz(1.0, 2.0, 3.0);
double t(4.0);
V4 xyzt(xyz, t);
return 0;
}
the class V4 contains another class V3, and the object of V4 is initialized by an exist object of V3, so the V4's constructor will call V3's copy constructor, and I think the copy constructor will be called once, but the result shows it's called tiwce, why is it?
compile the code:
g++ V4.cpp -o V4 -Wall
and run:
./V4
and the result:
V3(double, double, double)
V3(const V3 &)
V3(const V3 &)
V4(V3, double)
so look the result, why the V3 copy constructor is called twice? my OS is Lubuntu16.04,and g++ is 5.4.0
You're taking V3 a
by value in V4
's constructor, resulting in an additional unnecessary copy. You should take it by const&
:
class V4 {
private:
V3 xyz;
double time;
public:
V4(const V3& a, double t): xyz(a), time(t) {
// ^^^^^^^^^^^
cout << "V4(V3, double)" << endl;
}
};
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