Subquery returned more than 1 value error. How to solve this?
SELECT top 1 address
FROM tblAdr A
WHERE A.pkey=
(SELECT b.pkey FROM tblMachine b WHERE b.ADDRESS_PKEY IS NULL
)
The subquery (the quantity in parentheses) is returning more than one pkey
value, which isn't allowed because a single scalar value is required. If you are content with checking whether a pkey
in tblAdr
matches any of the values in the subquery, then you can use WHERE A.pkey IN (...)
as follows:
SELECT TOP 1 address
FROM tblAdr A
WHERE A.pkey IN (SELECT b.pkey FROM tblMachine b WHERE b.ADDRESS_PKEY IS NULL)
Change the =
to an IN
select top 1 address from tblAdr A where A.pkey in (select b.pkey from tblMachine b where b.ADDRESS_PKEY is null)
This should fix the error, however the logic of your query is likely flawed. You are after one row only ( select top 1
), however you don't define what row should be chosen first (no order by
clause).
Use IN
instead of =
as your subquery returns multiple matching rows.
SELECT top 1 address
FROM tblAdr A
WHERE A.pkey IN
(SELECT b.pkey FROM tblMachine b WHERE b.ADDRESS_PKEY IS NULL
);
Also, always use top queries with order by.
此子查询“从tblMachine b中选择b.pkey,其中b.ADDRESS_PKEY为null”返回多个值,您无法将其与“ =”运算符进行比较,但您需要此try in子句
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