Remove element from array if contains some string/symbol

Question

I have an array containing some words and I want to remove the words that contain either a . (fullstop) or ; (semicolon) or some other symbols. I have read the solution on [ Remove item from array if item value contains searched string character ] but this doesn't seem to answer my problem.

What can I add to this code to remove also the words containing the other symbols other than semicolon?

function myFilter($string) {
  return strpos($string, ';') === false;
}

$newArray = array_filter($array, 'myFilter');

Thanks

Answer 1

Use preg_match function:

function myFilter($string) {
    return !preg_match("/[,.]/", $string);
}

[,.] - character class which can be extended with any other symbols

Answer 2

// $array is your initial array
$newArray = array();
foreach ($array as $item){
    if ((strpos($item, ';') > 0)||(strpos($item, '.') > 0))
        continue;
    $newArray[] = $item;
}

// Words with ; or . should be filtered out in newArray
print_r($newArray);