How to use regex using awk

Question

I have a file, say test.txt which looks like a json and it contains a single line of data:

{"a":"b"},{"c":"d, e, f"},{..} and so on

I need to save all the data within each pair of braces in a different file in separate lines.

For eg: result.txt having

"a":"b"
"c":"d, e, f"

I used awk with regex in bash scripting

awk '/\{(.*?)\}/' test.txt  > result.txt

But instead of cropping up individual braces, it's printing the exact test file as it is.

Can anyone say what's going wrong?

Answer 1

echo '{"a":"b"},{"c":"d e f"},{..}' |awk -v RS="{|}" '{gsub(/,/,"")} /./{print $0}'
"a":"b"
"c":"d e f"
..

Note: It's a good idea to use json editing tools like jq to play around with json files.

Answer 2

或者，您可以使用带有环视的grep来仅捕获大括号之间的值：

grep -oP '(?<={).*?(?=})' test.txt > result.txt