Python - How to convert unicode to hexadecimal

Question

How do I convert unicode (Chinese characters) into hexadecimal using Python? I have been searching around for few days, but no luck.

Example:

Before convert: 耳环测试

After convert: 8033 73AF 6D4B 8BD5

I get the result using the following unicode online convertor tool: http://r12a.github.io/apps/conversion/

But I didn't manage to get it in my python code.

I tried using "binascii.hexlify(data)" but the result is "e880b3e78eafe6b58be8af95". I didn't manage to get the 4 digits hexadecimal.

my code:

s1 = "耳环测试"
s2 = binascii.hexlify(s1)
print s2 # Result: e880b3e78eafe6b58be8af95

I am using python 2.7 (Google App Engine). How do I convert "e880b3e78eafe6b58be8af95" to "8033 73AF 6D4B 8BD5" ?

Does anyone know how to solve this?

Thank you!

Joel

Answer 1

8033 73AF 6D4B 8BD5是UTF-16代码点，python为你提供了UTF-8。