Replacing a number in random.randint with a letter python

Question

import random

for i in range(1):

    myNum= str(random.randint(1,5))

    print(myNum)

Wanted to replace every occurrence of the number 1 with the letter j in python, how would one go about doing this?

Answer 1

Another option is to just select from the options you want in the first place:

myNum = random.choice(('j', '2', '3', '4', '5'))

# Equivalently, assuming they're all one character values:
myNum = random.choice('j2345')

Might even run a touch faster, since there are no type conversions needed (and a tuple of literal constants is cached in the function/module constants at least on CPython, so it won't be reconstructed over and over).

Answer 2

So long as it is just a single character from a string length up to 9, you can do:

my_chr='j2345'[random.randint(0,4)]

Just make sure that the string is the same length as the potential range of the random int.

Answer 3

Just use an if statement:

     import random

     for i in range(1):
          myNum = random.randint(1, 5)
          if myNum == 1:
              print("j")