I've a problem to do partial matches from a list of strings to a dataframe.
My df has this structure:
> df
mrun address stat
8988741 cerro pedregal 8536 , Antofagasta, Antofagasta OK
17625851 rancagua 2777 , Iquique, Tarapacá OK
9423953 picarte 4100 , Valdivia, Los Ríos OK
3459140 balmaceda 935 , Temuco, La Araucanía OK
24507700 rancagua 1940, La Serena, Coquimbo OK
and I have a list of strings with this values:
> address_list
c("balmaceda", "rancagua", "bombero garrido")
How can i select the rows than matched with any elements in the list?
This is my desire output:
> df_solution
mrun address stat
17625851 rancagua 2777 , Iquique, Tarapacá OK
3459140 balmaceda 935 , Temuco, La Araucanía OK
24507700 rancagua 1940, La Serena, Coquimbo OK
Edit: The solution given by saurav shekhar works for an address_list with few elements. In my case, my real address_list has above 5000 rows and df has 200000 rows and grep throws this error:
> df$flag[grep(address_list,df$address)]<- 1
Error in grep(address_list,df$address) :
invalid regular expression, reason 'Out of memory'
I have a lot of RAM so i don't think about it. I looked for an solution but i didn't find any way to do it. The only close thread in SO is this link , but i didn't know how to apply to my case.
My session info:
> sessionInfo()
R version 3.3.2 (2016-10-31)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows >= 8 x64 (build 9200)
locale:
[1] LC_COLLATE=Spanish_Latin America.1252 LC_CTYPE=Spanish_Latin America.1252
[3] LC_MONETARY=Spanish_Latin America.1252 LC_NUMERIC=C
[5] LC_TIME=Spanish_Latin America.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] gridExtra_2.2.1 ggplot2_2.2.0 plyr_1.8.4 reshape_0.8.6
First thing you need to do is to create matching variable in following format:
address_list<- paste(address_list, collapse = ",")
address_list<- gsub("," , "|" , address_list)
address_list<- c("balmaceda|rancagua|bombero|garrido")
Then using grep
you can do a partial matching on your data and create a flag for rows to keep.
# grep(address_list,df$address) Try this and note the output for your understanding of `grep`
df$flag<- NA
df$flag[grep(address_list,df$address)]<- 1 #flag rows with matching values
df_new<- df[which(df$flag==1),]
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