What does the code print? Exercise in C

Question

I am not sure why does this code print "h=13" and not "h=2". Does anyone have an idea?

#include <stdio.h>

int main() {
int j,h=1;
for(j=0;j<50;j++) {
        if(j%6==1) continue;
        h++;
        if(j==7 || j==14 || j==21)
               break;
}
printf("h=%d",h);
return 0;
}

Answer 1

1. When j = 0 neither of the if statements return a value of 1, and thus h is incremented.
2. When j = 1 in (j % 6 == 1) , 1 % 6 will give a remainder of 1 . The statement j % 6 is true and so, h is not incremented . (the '%' is a Remainder Operator)
3. When j = 2 to j = 6 neither of the if statements return a value of 1, and thus h is incremented.
4. When j = 7 in (j % 6 == 1) , 7 % 6 will give a remainder of 1 . The statement j % 6 is true and so, h is not incremented .
5. When j = 8 to j = 12 neither of the if statements return a value of 1, and thus h is incremented.
6. When j = 13 in (j % 6 == 1) , 13 % 6 will give a remainder of 1 . The statement j % 6 is true and so, h is not incremented .
7. For j = 14 the statement j == 14 is true and thus the break statement is executed.

h will be incremented for : j = 0, j = 2 to j = 6, j = 8 to j = 12, j = 14 which is a total of 12 times.

Total of 12 + 1 ( h = 1 ) = 13