//takes out random letters if taking out all of the vowles does not get it to the right number of charachters
while(tweet.length()> TWEET_LENGTH && vowles == 0){
int i = ranNum.nextInt(tweet.lenght());
char c = tweet.charAt(i);
if ((c !=''))
{
tweet = tweet.substring(0,i) + tweet.substring(i+1);
this is the code i have and i keep getting an error at this point
if ((c !=''))
where the two single quotes are saying "invalid character constant" I'm not sure what i am doing wrong. any tips?
There is no empty character. Based on the comment, you should be using 'a', 'e', 'i' ...
There is no such thing as a blank character. It is possible to have an empty String - that would be a String with zero characters in it. But a character always has a value.
Even if your code somehow compiled, it would be checking for an impossibility - tweet.charAt(i)
is going to return the character at location i
. How could there not be a character at that location? (If it was off the end of the String, it would throw an exception.)
If you wanted to check for a space, you could use ' '
instead of ''
. A space is a valid character that the compiler is happy to let you use.
The following code compiles and runs (but doesn't extract the vowels; you didn't show us that code and it's outside the scope of this question anyway.) It's almost identical to what you have, except I changed that ''
to ' '
and added the obvious stuff to make it compile.
import java.util.Random;
public class Answers
{
public static void main(String[] args)
{
Random ranNum = new Random();
String tweet = " \"So the combination is... one, two, three, four, five? That's the stupidest combination I've ever heard in my life! That's the kind of thing an idiot would have on his luggage!\"";
final int TWEET_LENGTH = 140;
while(tweet.length() > TWEET_LENGTH){
int i = ranNum.nextInt(tweet.length());
char c = tweet.charAt(i);
if ((c !=' '))
{
tweet = tweet.substring(0,i) + tweet.substring(i+1);
}
}
System.out.println(tweet);
System.out.println(tweet.length());
}
}
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