Checking for Int in Array . Swift 3, iOS

Question

I have the following code:

print (sender.tag) // prints 21  (example)
print(DictPl2) // prints [0, 1, 20, 21, 84, 94, 26, 27, 37, 55, 56, 66, 52, 53, 54, 55, 72, 73, 74, 75]
var DictPl2 = [Int]()
if playeractive == 1 {
 for i in DictPl2 {
                if i == sender.tag {
                    print("Well done")
                    sender.backgroundColor = UIColor.red

                }

                else {    //always goes this
                    print("Bad")
                    sender.backgroundColor = UIColor.brown
                }
            }

I am checking if sender.tag does equal to any of elements in array DictPl2. But if it does or doesn't equal, the code always goes the marked way. Anyone knows, what might be the mistake? Thank you

Answer 1

You can just use DictPl2.contains(sender.tag) instead of your for loop . Then your code would look like:

if DictPL2.contains(sender.tag) {
    print("Well done")
    sender.backgroundColor = UIColor.red
} else {
    print("Bad")
    sender.backgroundColor = UIColor.brown
}

Answer 2

In Swift 3.2

if DictPL2.contains(where: {$0 == sender.tag) {
    print("Well done")
} else {
    print("Bad")
}

Please check Apple Guide .