How to write a SQL statement for listing all Makes that have more than three Types

Question

How to write a SQL statement for listing all Makes that have more than three Types

below is the table of data

Make           Model                            Type
Chrysler       Crossfire 2dr                    Sports
Ford           Crown Victoria 4dr               Sedan
Ford           Crown Victoria LX 4dr            Sedan
Ford           Crown Victoria LX Sport 4dr      Sedan
Honda          CR-V LX                          SUV
Cadillac       CTS VVT 4dr                      Sedan
Dodge          Dakota Club Cab                  Truck
Dodge          Dakota Regular Cab               Truck
Cadillac       Deville 4dr                      Sedan
Cadillac       Deville DTS 4dr                  Sedan
Mitsubishi     Diamante LS 4dr                  Sedan
Land Rover     Discovery SE                     SUV
Dodge          Durango SLT                      SUV
Mercedes-Benz  E320                             Wagon
Mercedes-Benz  E320 4dr                         Sedan
Mercedes-Benz  E500                             Wagon

Answer 1

You need to group your rows by make & type and then use having in your sql. something like this:

SELECT make FROM cars
GROUP BY make
HAVING COUNT(type) > 3

HAVING is like WHERE when grouping

EDIT: removed type column from GROUP BY

Answer 2

Use the following query

SELECT make FROM cars
GROUP BY make
HAVING COUNT(type) > 3

Side Note: In general, All column names in SELECT list must appear in GROUP BY clause unless name is used only in an aggregate function

The SQL GROUP BY clause is used in collaboration with the SELECT statement to arrange identical data into groups. The GROUP BY clause follows the WHERE clause in a SELECT statement and precedes the ORDER BY clause.

Learn more about Group BY in this link

Answer 3

I assume you mean more than three different types. So use COUNT DISTINCT in the HAVING clause:

SELECT make
FROM cars
GROUP BY make
HAVING COUNT(DISTINCT type) > 3