I have such a function:
def get_temperature(s):
parts = re.findall(r'([+-]?\d+(\.\d+)*)\s?°([CcFf])', s)
for a in range(len(parts)):
s = s.replace(parts[a], "qTEMPq")
return s
The input parameter s
for the function is a string value. The output parameter is also a string value.
So at the end, if I have a string like "It is +25°C outside."
as an input, the output string will be "It is qTEMPq outside."
The regular expression I am using from extracting temperature degrees (celcius or fahrenheit) from string finds the subparts similar to (40°F, +30°C, -35 °C, etc.). It works perfectly in regexr.com
, but not in my code.
What might be the problem, and how can I solve it?
If you have more than 1 group (...) in your regex, findall will return a list of tuples.
If you want to obtain a list of strings, you can make the groups non-capturing using (?:...), as in:
import re
def get_temperature(s):
parts = re.findall(r'(?:[+-]?\d+(?:\.\d+)*)\s?°(?:[CcFf])', s)
for a in range(len(parts)):
s = s.replace(parts[a], "qTEMPq")
return s
get_temperature('40.5°F')
# 'qTEMPq'
get_temperature('100°F is nearly 37°C')
# 'qTEMPq is nearly qTEMPq'
get_temperature("It is +25°C outside.")
# 'It is qTEMPq outside.'
If what you want is to access the parts of the temperature, you could do (in order to have tuples with value and unit):
def get_temperature(s):
parts = re.findall(r'([+-]?\d+(?:\.\d+)*)\s?°([CcFf])', s)
return parts
get_temperature("It is +25°C outside.")
#[('+25', 'C')]
Or, if you just want to have the whole temperature as a string:
def get_temperature(s):
parts = re.findall(r'(?:[+-]?\d+(?:\.\d+)*)\s?°(?:[CcFf])', s)
return parts
get_temperature('100°F is nearly 37°C')
# ['100°F', '37°C']
import re
def get_temperature(s):
return re.sub(r'[+-]?\d+\.*\d*\s?°[CcFf]', 'qTEMPq', s)
Is this what you're looking for?
I have solved the problem, by using " \\xb0
" instead of " °
". It was an encoding issue. So basically, instead of using '[+-]?\\d+\\.*\\d*\\s?°[CcFf]'
expression, I have used '[+-]?\\d+\\.*\\d*\\s?\\xb0[CcFf]'
.
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